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OpenStudy (desmarie):
Simplify the following expression.
rad3 times 2rad2
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OpenStudy (jclark):
Have you ever seen this notation?\[x^{\frac{ 1 }{ 3 }}\times x ^{\frac{ 1 }{ 3 }}\]
OpenStudy (desmarie):
the options they give to choose an answer from are:
6rad2
rad12
6rad5
2rad6
OpenStudy (desmarie):
no I dont thinks so.....
OpenStudy (desmarie):
*think
OpenStudy (jclark):
here's the general rule: \[\sqrt{x }\times \sqrt{y} =\sqrt{xy}\]
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OpenStudy (jclark):
so the whole thing reads \[\sqrt{3} \times 2 \times \sqrt{2}\]
OpenStudy (desmarie):
ok..i am following you so far :)
OpenStudy (jclark):
you can multiply things in any order, so it could be \[2 \times \sqrt{3} \times \sqrt{2}\]
OpenStudy (jclark):
now use the general rule I showed you. What should the radical be now?
OpenStudy (jclark):
hint: x is 3 and y is 2
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OpenStudy (desmarie):
sorry.....the answer is 2rad6....right?
OpenStudy (jclark):
if x=3 and y=2 then \[\sqrt{x} \times \sqrt {y} = \sqrt {3} \times \sqrt{2} = \sqrt {xy} = \sqrt {3 \times 2}\]
OpenStudy (jclark):
you tell me...
OpenStudy (desmarie):
I would say 2rad6
OpenStudy (jclark):
And you would be correct.
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OpenStudy (desmarie):
thanks so much for your help
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