Simplify the following expression. rad3 times 2rad2
Have you ever seen this notation?\[x^{\frac{ 1 }{ 3 }}\times x ^{\frac{ 1 }{ 3 }}\]
the options they give to choose an answer from are: 6rad2 rad12 6rad5 2rad6
no I dont thinks so.....
*think
here's the general rule: \[\sqrt{x }\times \sqrt{y} =\sqrt{xy}\]
so the whole thing reads \[\sqrt{3} \times 2 \times \sqrt{2}\]
ok..i am following you so far :)
you can multiply things in any order, so it could be \[2 \times \sqrt{3} \times \sqrt{2}\]
now use the general rule I showed you. What should the radical be now?
hint: x is 3 and y is 2
sorry.....the answer is 2rad6....right?
if x=3 and y=2 then \[\sqrt{x} \times \sqrt {y} = \sqrt {3} \times \sqrt{2} = \sqrt {xy} = \sqrt {3 \times 2}\]
you tell me...
I would say 2rad6
And you would be correct.
thanks so much for your help
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