Question

help please

i need help with 2b
http://prnt.sc/chmhxa

idk what i did wrong

Answer 1

i did the washer method

Answer 2

where's the question?

Answer 3

heres my work

Answer 4

looks like you got tbh...

Answer 5

wym lool my answer isnt matching the answer key D:

Answer 6

I didn't see an answer key

Answer 7

ik lol thats my work but my answer key says 117pi/5

Answer 8

Take a bigger pic... so i can zoom in and read your work more clearly

Answer 9

iight one sec

Answer 10

is it still blurry ?

Answer 11

same

Answer 12

think it might be my phone

Answer 13

Would be a lot easier if you didn't photograph the entire page, do top and bottom half

Answer 14

Your limits look wrong. Should be from y=-1 to y=2... but again i can't read them.

Answer 15

hmm how did you get them limits ?

Answer 16

By looking at where the functions intersect on the graph.

Answer 17

hmm is there a way to solve for it ?

Answer 18

How the hell did you get your limits??

Yeah... you set the functions equal to each other. You're solving for y.

Answer 19

thats what i did lool


i did this which ik all my equation is gonna be in terms of y

so i did this

\[1+y^2=y+3\]

Answer 20

Neega... you can't write
y(y-1) = 2
and then say y=2 and y-1=2, tf, this is basic algebra.

Look at your graph! Didn't you notice where curve and the line intersect? x'd

Answer 21

loool. then how tf would you solve it x'd ... i struggle with my algebra x'd

Answer 22

looool you get it equal to zero!

Tell me on the attached graph where they intersect, the y values. It's pretty clear.

Answer 23

Why draw a graph if you ain't even gonna pay attention to it x'd

Answer 24

loool x'd

okay okay so then to solve it " algebraically " .. show me x'd

Answer 25

\[\large 1+y^2=y+3\]\[\large y^2-y -2=0\]

Answer 26

Solve it like you would any damn quadratic x'd get all them neegas on one side

Answer 27

oh gawd quad fromula... D:

Answer 28

wait jk lool got it x=- 1 x= 2

Answer 29

No, just factor gurl

And you better learn from this. Next time, look at your graph, estimate the limits from it, THEN do it algebraically.

Answer 30

They're y's gurl not x

Answer 31

x'd lool yesh.. y's im use to seein x's a lot haha

Answer 32

how the hell did you not notice on your graph that y=2 and y=3 are not even inside the region enclosed by the graphs x'd

Answer 33

x'd idk loool i saw too much work.. got me @_@

Answer 34

so for these how tf would you know if you are gonna use cylindrical shells , washer/disks ?

Answer 35

It's your choice. You pick the one that's easier. Sometimes the integral for one will be too difficult to solve.

Answer 36

Sometimes they're both the same difficulty.

Answer 37

ohhh x'd

Answer 38

iight help me with this one x'd

2c http://prnt.sc/chmhxa

Answer 39

Make a new question ;P