Question

2(x-y) over square root x minus square root of y

Answer 1

What is the question?

Answer 2

\[\frac{ 2(x-y) }{ \sqrt{x}-\sqrt{y} }\]

Answer 3

yes that is the question. Can you please help me?

Answer 4

This is a forumla....WHERE IS THE QUESTION???

Answer 5

\[ \frac{ 2\left( x-y \right) }{ \sqrt{x}-\sqrt{y} }=\frac{ 2\left\{ \left( \sqrt{x} \right)^2-\left( \sqrt{y} \right)^2 \right\} }{ \sqrt{x} -\sqrt{y}}\]
\[=\frac{ 2\left( \sqrt{x}+\sqrt{y} \right)\left( \sqrt{x}-\sqrt{y} \right) }{ \left( \sqrt{x} -\sqrt{y}\right) }=?\]

Answer 6

it says to rationalize the denominator

Answer 7

ok ,you can do that way also.
multiply the numerator and denominator by \[\sqrt{x}+\sqrt{y}\]

Answer 8

so it wants simplification

Answer 9

okay so that would be \[2(\sqrt{x}+\sqrt{y}) \over (\sqrt{x}-\]

Answer 10

oops minus square root of y

Answer 11

Thanks sooo much!!!

Answer 12

as i have done\[\sqrt{x}-\sqrt{y}\]
cancels from the numerator and denominator

Answer 13

Okay how about this...
Rationalize the numerator
\[\sqrt{x}-\sqrt{x+h} \over h \sqrt{x}\sqrt{x+h}\]

Answer 14

multiply the numerator and denominator by
\[(\sqrt{x}+\sqrt{x+h})\]

Answer 15

okay thanks