Question

will fan and medal or give snapchat to whoever helps!
Almost done with a limit problem, anyone know how to proceed?
http://puu.sh/ralUZ/4797b70993.png

Answer 1

Start with the continuity part. It has to be continuous at x=1, since that's the boundary between the two functions. So plug in x=1 into both, and set them equal to each other:
\[\large (1)^2 -2(1)-a = -(1)^2 +b(1) +2\]and simplify as far as you can\[\large -2 = a+b\]Now we can move onto the differentiability part.

Answer 2

Differentiable means the derivatives of both at must be equal, so find the derivatives, then plug in x=1 and set them equal

Derivative of the top one is 2x - 2
Derivative of the bottom one is -2x +b

\[\large 2(1) - 2 = -2(1) + b\]Now you can solve for b, then go back above and solve for a.

Answer 3

@czesc...?

Answer 4

@agent0smith thank you so much!!!

Answer 5

Welcome.