In baseball, a player’s batting average is calculated by dividing the number of hits by the number of at-bats. The table shows Player A’s batting average and number of at-bats for three regular seasons.

| Season | Average | At Bats |
| 2010 | .312 | 596 |
| 2011 | .296 | 446 |
| 2012 | .295 | 599 |

Player A had 132 hits in 2011

b.Player B had 33 fewer hits in the 2011 season than Player A but had a greater batting average. Your friend concludes that Player B had more at-bats in the 2011 season than Player A. Is your friend correct? Explain

Question

In baseball, a player’s batting average is calculated by dividing the number of hits by the number of at-bats. The table shows Player A’s batting average and number of at-bats for three regular seasons.

| Season | Average | At Bats | 
| 2010    | .312      | 596      | 
| 2011    | .296      | 446      | 
| 2012    | .295      | 599      | 

Player A had 132 hits in 2011

b.Player B had 33 fewer hits in the 2011 season than Player A but had a greater batting average. Your friend concludes that Player B had more at-bats in the 2011 season than Player A. Is your friend correct? Explain

sarah18 · Answer

Here is the first part of the question:
a. How many hits did Player A have in the 2011 regular season? Round your answer to the nearest whole number.
My answer: .296*446=132.016
I understood that, but in part b I don't understand how to figure out how to find how many at-bats player B had...