Question

In baseball, a player’s batting average is calculated by dividing the number of hits by the number of at-bats. The table shows Player A’s batting average and number of at-bats for three regular seasons.

| Season | Average | At Bats |
| 2010 | .312 | 596 |
| 2011 | .296 | 446 |
| 2012 | .295 | 599 |

Player A had 132 hits in 2011

b.Player B had 33 fewer hits in the 2011 season than Player A but had a greater batting average. Your friend concludes that Player B had more at-bats in the 2011 season than Player A. Is your friend correct? Explain

Answer 1

Here is the first part of the question:
a. How many hits did Player A have in the 2011 regular season? Round your answer to the nearest whole number.
My answer: .296*446=132.016
I understood that, but in part b I don't understand how to figure out how to find how many at-bats player B had...

Answer 2

So part a is correct. For part b you don't really need to find anything tbh. For player b to have a higher batting average, his hits and at-bats would need to be closer than player a's. Player a has 132 hits (you found this in a) and 446 at bats.

Player b has 99 hits (132 -33 (says player b had 33 fewer hits than a)). So even at 99 hits let's do 99/446 we end up with a .2219 batting average, so we automatically conclude that your friend is wrong, he has fewer at bats than player a.

Hopefully this makes sense! If not, I'll explain better.

Answer 3

@Sarah18 Do you understand?

Answer 4

Yes, thank you so much!! I've been trying to figure it out since yesterday. You are very helpful!