Question

In a

Answer 1

72 A

Answer 2

stop giving direct answers u kawnt

Answer 3

Unless I'm mistaken, the allele frequency gives a measure of how many copies of a given allele occurs in a population.

What that means is that any individual with the genotype \(\mathrm{RR}\) contributes twice as much to the frequency of \(\mathrm{R}\) than a heterozygous individual with genotype \(\mathrm{Rr}\).
\[\text{frequency of }\mathrm{R}=2\text{ frequency of }\mathrm{RR}+\text{frequency of }\mathrm{Rr}\]
But don't hold me to this - the problem is that simply knowing that \(72\%\) of the population has red eyes doesn't tell you how many lizards are homozygous dominant and how many are heterozygous...

Answer 4

Looks like I had the wrong equation in mind... This is actually a fairly standard Hardy-Weinberg problem.

Let \(p\) be the frequency of the dominant allele and \(q\) the frequency of the recessive allele. Then under H-W conditions,
\[\begin{cases}p+q=1\\p^2+2pq+q^2=1\end{cases}\]Given that \(0.72\) of the population has red eyes, you know that \(p^2+2pq=0.72\) because \(p^2+2pq\) gives the frequency of both genotypes \(\mathrm{RR}\) and \(\mathrm{Rr}\).

You can then solve for \(q\) and use that to solve for \(p\).
\[0.72+q^2=1\implies q=\cdots\implies p=1-q=\cdots\]

Answer 5

au would it be .47??

Answer 6

That's correct.

Answer 7

thank you.

Answer 8

can I ask you one more?

Answer 9

Sure

Answer 10

thanks

Answer 11

thats all

Answer 12

I thought it was A. but I'm unsure...

Answer 13

do you have any ideas?

Answer 14

If longer legs help the crickets to escape predation, then selective pressures will reinforce a trend of longer legs in successive generations.

The graph you selected has the opposite result - this graphs shows that more insects will have shorter legs as time goes on, but that would only make them easier prey.