In the square pyramid shown below, the diagonal length FC = 16√2 centimeters and the height of the pyramid is 7 centimeters. Find the slant height AD of the pyramid, to the nearest tenth. Show your work with reasoning for each step.

Question

the_rebel_outlaw · Answer

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jhonyy9 · Answer

FC = 16sqrt2 

base side length let be s 

s^2 +s^2 = FC^2

2s^2 = 2*16^2  divide both sides by 2 

s^2 = 16^2 

s = 16 cm from this result that the length of OD = 16/2 = 8 cm 

the height AO so  h = 7 cm 

using in triangle AOD the pythagoras theorem 

AD^2 = h^2 + OD^2

AD^2 = 7^2 +8^2

AD^2 = 49 +64 

AD = sqrt 113 

AD = 10,6 cm 

hope helped

jhonyy9 · Answer

ok. ? this is understandably sure right easy ?

the_rebel_outlaw · Answer

yea, the way my teacher explained it was confusing, i honestly don't even remember how she explained it. Thank you

jhonyy9 · Answer

np

was my pleasure and anytime than i m here online just tag me 

good luck

bye bye

the_rebel_outlaw · Answer

bye