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Chemistry 19 Online
OpenStudy (kittiwitti1):

http://prntscr.com/ciemwm I literally tried to solve this three times and kept getting that answer...

OpenStudy (kittiwitti1):

@cuanchi ?

OpenStudy (cuanchi):

let me see,

OpenStudy (kittiwitti1):

alright take your time

OpenStudy (cuanchi):

apparently the reaction stoichiometry is 1:1 then the number of moles of BaSO4 in 0.2193 g will be equal to the number of moles of MSO4 in 0.1131g Calculate the molecular mass of MSO4 and substract the mass of the SO4 you will get the mass of M

OpenStudy (kittiwitti1):

wait so mass MSO4 = mass BaSO4? (molecular mass*)

OpenStudy (kittiwitti1):

cause the directions I used for this told me to get SO4 mass, then subtract from MSO4 to get M mass, then use that to find moles M

OpenStudy (cuanchi):

NO!!! moles

OpenStudy (kittiwitti1):

then from that divide M mass by M moles to get the answer

OpenStudy (kittiwitti1):

I would send a pic but idk how xD

OpenStudy (cuanchi):

yes it is other way

OpenStudy (kittiwitti1):

I keep getting 96.04-96.06 range

OpenStudy (cuanchi):

do you want me to calculate?

OpenStudy (kittiwitti1):

oh ... okay o:

OpenStudy (kittiwitti1):

yeah, maybe I am doing something wrong o_o

OpenStudy (cuanchi):

24.38 = Mg

OpenStudy (kittiwitti1):

They just want the molecular mass lol

OpenStudy (cuanchi):

what is the metal with a molecular mass of 24.3?

OpenStudy (kittiwitti1):

it says "wrong" 2 tries left

OpenStudy (cuanchi):

let me try again

OpenStudy (kittiwitti1):

I got 0.001248 mol BaSO4 from the given amount 0.2193 g of BaSO4

OpenStudy (cuanchi):

n=m/MM n= 0.2193 g/ 233.39 g = 9.396 x 10^-4 moles

OpenStudy (kittiwitti1):

Sorry. My school computer is a gigantic butt and wouldn't let me on here for a total 3 minutes

OpenStudy (kittiwitti1):

Wait, what is that? o_o

OpenStudy (cuanchi):

n=m/MM n= number of moles m= mass MM= molecular mass

OpenStudy (kittiwitti1):

Hmm I'm not sure what I did wrong the first time around. I got that m/MM value also

OpenStudy (kittiwitti1):

So maybe that's where I messed up

OpenStudy (kittiwitti1):

Alright I got \(\huge{\color{blue}{120.37g}}\) from the following equation\[\Large{\frac{0.1131}{0.0009396}}\]

OpenStudy (cuanchi):

ok, now you have to subtract the mass of one mole of SO4

OpenStudy (kittiwitti1):

\[\Large{120.37(MSO_{4})-96.07(SO_{4})=24.3}\]

OpenStudy (kittiwitti1):

so... 24.3?

OpenStudy (cuanchi):

OK we are talking about significan figures now?

OpenStudy (kittiwitti1):

yes

OpenStudy (kittiwitti1):

24.30 I believe, but I'm not sure. All given values in the problem are 4-digit decimals

OpenStudy (kittiwitti1):

4-significant figure-digit*

OpenStudy (cuanchi):

yes that it is Mg molecular mass

OpenStudy (kittiwitti1):

we got 24.38 last time lol

OpenStudy (kittiwitti1):

Oh, it does say on the "hint" part after that answer: "Not quite. Try checking your rounding" or something like that

OpenStudy (kittiwitti1):

so 24.30 is better?

OpenStudy (cuanchi):

because I used 9.39 x 10^-4 in place of 9.396 x 10^-4

OpenStudy (kittiwitti1):

this website is way too stingy about answer digits -_-

OpenStudy (kittiwitti1):

Thank you :) I still have another oxidation question if that's okay?

OpenStudy (cuanchi):

It is that Masterinchemistry?

OpenStudy (kittiwitti1):

yes lol

OpenStudy (cuanchi):

what book?

OpenStudy (kittiwitti1):

http://prntscr.com/cif67f Petrucci 10th edition

OpenStudy (cuanchi):

Nivaldo Tro?

OpenStudy (cuanchi):

OK

OpenStudy (cuanchi):

+3

OpenStudy (kittiwitti1):

it says to make \(x\) for Carbon and \(y\) for Oxygen

OpenStudy (kittiwitti1):

and I know Oxygen is -2, so \(y=-2\)

OpenStudy (kittiwitti1):

so I thought \(x=-5\) by calculation

OpenStudy (cuanchi):

yes O is allays -2 2x + 4y = -2

OpenStudy (kittiwitti1):

yes

OpenStudy (kittiwitti1):

2x+4y= -2 2x= -4y-2 2x = -4(2)-2 2x = -8-2 2x = -10

OpenStudy (kittiwitti1):

\[\Large{x=-\frac{10}{2}=-5}\]

OpenStudy (cuanchi):

you said x=C y=O 2x + 4 (-2) =-2 x= (-2 -(4 (-2))) /2 x= (-2 + 8) /2 x= 6/2 =3

OpenStudy (kittiwitti1):

... I realize I forgot to make y a NEGATIVE 2

OpenStudy (kittiwitti1):

I'm sorry; I'm silly lol

OpenStudy (kittiwitti1):

Thank you :)

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