Some friends tell you that they paid $28146 down on a new house and are to pay $637 per month for 30 yrs. The selling price of the house is $137,897.81 . How much interest will they pay in 30 years?
I multipled and subtracted ($637x12x30) - $137,897.81 but the answer wasn't right
http://www.thecalculatorsite.com/articles/finance/compound-interest-formula.php
@kittiwitti1 So the formula I'd use would be A = P (1 + r/n)^nt ?
Yup
@kittiwitti1 I'm still lost lol Is A= 137897.81 P=637 nt= 12(30)
Did you calculate with that information?
i got 3507.72
Is it correct? Sorry, I'm working on another subject at the moment.
I forgot to mention that the rate was 5.7% compounded monthly
No it isn't :( It's okay lol
Seems like you included that in the \(t\) part
wouldn't t= years?
I meant \(n\)... please don't kill me ;-;
I did 637(1 + (0.57/12))^(12*30)
Odd. That should've worked.
i was told that it would be (637*m*t) -$137,897.81 but it isn't giving me the correct answer
@.Sam.
Sorry. I'd help but I'm in a hurry and I don't want to abandon you... ahah
Good luck~ ; -;
@kittiwitti1 Thank you for all your help!
@mathmate
@jhonyy9
`Some friends tell you that they paid $28146 down on a new house and are to pay $637 per month for 30 yrs. The selling price of the house is $137,897.81 . How much interest will they pay in 30 years? ` you answered `I multipled and subtracted ($637x12x30) - $137,897.81 but the answer wasn't right` It is almost right. except that the mortgage is for (137,897.81-downpayment). So you need to subtract this amount instead of 137,897.71.
@mathmate So I would subtract 137,897.71 from $28,146 first and then use the formula I started with (637x12x30)?
`So I would subtract 137,897.71 from $28,146 first and then use the formula I started with (637x12x30)?` House price: 137,897.71 downpayment:28,146 So he borrowed:137,897.71-28,146 (not the other way round). After that, you can use the method you started with, i.e. subtract amount borrowed FROM the total of the payments.
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