Need help with geometry! MEDAL will be awarded!
@agent0smith
@TheSmartOne @Nnesha
Very similar to some physics. I could probably help with the first part; I know what the second one means, but I am not so good at doing it.
What's the difference of x and y between all three points?
x = 3, 9, 15 y = 4, 8, 12.
I need help with the part that wants to find the position of the bug after t seconds.
Is that more so in a equation format?
I would guess so
Well, in every x value and y value, has a certain mathematical proof.
You learn this from the difference in the points.
I don't understand how this relates to the question.
It relates to the question in the relation of configuring the correct equation. Which the exponential way would not, sense the 3^3 does not equal 15, but it worked for the first two x's.
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I am sorry but I do not understand what you are trying to say. Please help me because I don't have a lot of time to answer these questions.
If you were trying to find every second value, you could by dividing the difference by 2. Since, the difference has only been shown with two second variables.
Which is (3,2)
+3 to the x value, +2 to the y value.
Say, you were looking for three seconds. (9,8) + (3,2) = (12,10)
(3,2) is equal to one second.
Hence, a constant velocity throughout the graph.
(x + 3) , (y + 2) = t.
That may be poorly configured. I apologize, one second.
@agent0smith Do you see a better way to form it? I am sure there is.
You could write parametric equations for the x and y: x = 3 + 3t (it starts at x=3, every second advances 2 units in the x direction) y = 4 + 2t (starts at y=4, every second advances 2 units in the y direction)
Ah, so you do use two different equations, I tried to uniform it within one. Thank you so much.
For part b, equidistant means x=y, so set them equal, solve for t. Parametric equations usually aren't introduced until precalc, though... and this is geometry.
So, 3 + 3t = 4 + 2t for the second part?
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@calculusxy Sorry for not answering swiftly, here is the solutions if you want to review them.
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