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Mathematics 13 Online
OpenStudy (calculusxy):

Need help with geometry! MEDAL will be awarded!

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@agent0smith

OpenStudy (calculusxy):

@TheSmartOne @Nnesha

OpenStudy (vuriffy):

Very similar to some physics. I could probably help with the first part; I know what the second one means, but I am not so good at doing it.

OpenStudy (vuriffy):

What's the difference of x and y between all three points?

OpenStudy (vuriffy):

x = 3, 9, 15 y = 4, 8, 12.

OpenStudy (calculusxy):

I need help with the part that wants to find the position of the bug after t seconds.

OpenStudy (vuriffy):

Is that more so in a equation format?

OpenStudy (calculusxy):

I would guess so

OpenStudy (vuriffy):

Well, in every x value and y value, has a certain mathematical proof.

OpenStudy (vuriffy):

You learn this from the difference in the points.

OpenStudy (calculusxy):

I don't understand how this relates to the question.

OpenStudy (vuriffy):

It relates to the question in the relation of configuring the correct equation. Which the exponential way would not, sense the 3^3 does not equal 15, but it worked for the first two x's.

OpenStudy (impracticaljoker):

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OpenStudy (calculusxy):

I am sorry but I do not understand what you are trying to say. Please help me because I don't have a lot of time to answer these questions.

OpenStudy (vuriffy):

If you were trying to find every second value, you could by dividing the difference by 2. Since, the difference has only been shown with two second variables.

OpenStudy (vuriffy):

Which is (3,2)

OpenStudy (vuriffy):

+3 to the x value, +2 to the y value.

OpenStudy (vuriffy):

Say, you were looking for three seconds. (9,8) + (3,2) = (12,10)

OpenStudy (vuriffy):

(3,2) is equal to one second.

OpenStudy (vuriffy):

Hence, a constant velocity throughout the graph.

OpenStudy (vuriffy):

(x + 3) , (y + 2) = t.

OpenStudy (vuriffy):

That may be poorly configured. I apologize, one second.

OpenStudy (vuriffy):

@agent0smith Do you see a better way to form it? I am sure there is.

OpenStudy (agent0smith):

You could write parametric equations for the x and y: x = 3 + 3t (it starts at x=3, every second advances 2 units in the x direction) y = 4 + 2t (starts at y=4, every second advances 2 units in the y direction)

OpenStudy (vuriffy):

Ah, so you do use two different equations, I tried to uniform it within one. Thank you so much.

OpenStudy (agent0smith):

For part b, equidistant means x=y, so set them equal, solve for t. Parametric equations usually aren't introduced until precalc, though... and this is geometry.

OpenStudy (vuriffy):

So, 3 + 3t = 4 + 2t for the second part?

OpenStudy (agent0smith):

\[\large \checkmark \]

OpenStudy (vuriffy):

@calculusxy Sorry for not answering swiftly, here is the solutions if you want to review them.

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