Question

Let a function g be defined by g(x)=2x^2-3x+10 find g'(x) when g(x)=15

Answer 1

So 2x^2-3x+10=15? Solve for x?

Answer 2

Yes

Answer 3

I'm just confused thought because you get more than 1 point? Is that ok?

Answer 4

Of ccause, and their sloe should be direct opposite

Answer 5

sorry, slope, my typo

Answer 6

becuase you are looking at a quartic equation

Answer 7

Ok let me try it out and see what I get

Answer 8

baddrawing but you get the idea

Answer 9

Ok so after factoring I got x=5/2 and x=-1

Answer 10

plug those into the derivative

Answer 11

So I got g'(5/2)=7 and g'(1)=-7

Answer 12

see, thats exactly what Im talking about

Answer 13

Yes, that totally made sense when you interpreted it with a graph

Answer 14

Thank you so much :)

Answer 15

no problem, now Im going to sleep before my head hits my keyboards;dl'fmceiksd'icmmkal'sklaskdnrfsow'kqd012
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Answer 16

Lol goodnoght!