An object starts from rest with a constant acceleration of 8.00 m/s along a straight line. Find (a) the speed at the end of 5.00 s, (b) the average for the 5¬s interval, and (c) the distance traveled in the 5.00 s.

Question

jiteshmeghwal9 · Answer

acceleration(a)=8 m/s^2
initial velocity =0

a).Here we can apply equation of motion as object is moving with constant acceleration
v=u+at
v=final speed
a= acceleration
t=time
u=initial speed

jiteshmeghwal9 · Answer

c). as we know object is moving with constant acceleration so

$s= ut+\frac{1}{2}at^2$
s=distance travelled
u=initial speed
a=acceleration
t=time

jiteshmeghwal9 · Answer

I just don't gt wht r u asking in part b.

I mean that average of which quantity do u want to find ?