Question

Geometry help. like two questions i need help with

Answer 1

@GracieJaylene
Do you know what \(T^{-2}\) means?

Answer 2

no ..

Answer 3

If we define
T:(x,y)->(x+1,y+1)
means a translation to the right 1 unit and up 1 unit.
In that case,
\(T^{-1}\) means the inverse transformation, or translating in the reverse direction.
\(T^{-1}:(x,y)->(x-1,y-1)\)

SImilarly, \(T^{-2}\) means applying the inverse transformation twice, namely

\(T^{-2}:(x,y)->(x-1,y-1) -> (x-1-1, y-1-1)\)
which simplifies to
\(T^{-2}:(x,y)->(x-2,y-2)\)

So you can work out the given problem similarly.

Answer 4

... im still confused though..

Answer 5

@Unavailabilityy

Answer 6

@AloneS

Answer 7

in mathmate's example each + 1 becomes -1 . That s the reverse of the translation

so in your question
the inverse of (x + 3, y + 1) is (x - 3,y - 1) - that is T-1

now apply the inverse transformation again by subtracting 3 from the first coordinate and subtract 1 from the second. This will give you T-2