Question

What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?

Answer 1

Na2CO3

Answer 2

https://answers.yahoo.com/question/index?qid=20091212232905AAjd5Gg

Answer 3

You need to find its mole ratio
assume 1% = 1 gram

Then it will be :

\[\frac{ 43.38 }{ 23 } : \frac{ 11.33 }{ 12 } :\frac{ 45.29% }{ 16 }\]

You will got the smallest mole ration :
2 : 1 : 3

So, the empiric formula will become
Na2CO3