Question

Help again. Please. Picture attached

Answer 1

@Unavailabilityy

Answer 2

hmm i dont remember doing anything like this, sorry hun let me ask some of my friends to see if they can help you okay :)

Answer 3

ok thanks

Answer 4

you're welcome :)

Answer 5

i have 5 more lessons to do then im graduated.. i need all the help i can get

Answer 6

wow congrats :) I will definitely find you some proper help

Answer 7

@princeharryyy

Answer 8

@Arcadiouse

Answer 9

hmm give him some time okay he takes awhile

Answer 10

forever is more like it lol

Answer 11

@RawrItsKai

Answer 12

what

Answer 13

could you help me with a different question?

Answer 14

i can try

Answer 15

Area = ½b × h
= ½ × 6 × 8
= 24

Answer 16

idk if i did this the proper way for the question but it's apparently 24

Answer 17

FOr the first question lateral surface area = 3 times area of three equilateral triangles

=> 3 * sqrt(3) * 4*4/4 = 12*sqrt(3)

area of equilateral triangle = sqrt(3) * a^2/4 where a is the side of an equilateral triangle .

@RawrItsKai @GracieJaylene

Answer 18

for second one >>
area of base of pyramid (i.e. hexagon) = 6* sqrt(3) *6*6/4 = 54 *sqrt(3)
side length of one face of a triangle = sqrt(8^2 +6^2) =10
so height of one face of a triangle = sqrt (10^2 - 3^2) = sqrt(91)
total area of six triangular faces = 6*(sqrt(91)*6/2)

area of pyramid = 54*sqrt(3) + 18*sqrt(91)

sqrt implies square root of