Solve for p. 3+|1+p|=12 p = 8 or p=−10 p = 14 or p=−16 p = 10 or p=−10 p = 8 or p=−8
Start by isolating |1+p|. Do this by subtracting 3 from both sides of your equation. Show your work, please.
3+1=4 so D
Not quite. We would isolate \(\large{|1+p|}\) so we would subtract 3 from both sides in order to get it to itself so.... \(\huge{(3-3)|1+p|=12-3}\) What would that equal?
(3-3=0) (1+p=?) (12-3=9)
\[\huge{(3-3)|1+p|=12-3}\]
is not correct. Both of you, please work on this to find and correct the error.
This post is newwar's; please help newwar solve the problem himself or herself.
Again, subtract 3 from both sides of the original equation.
I'm following mathmale around giving him medals :D
newwar? 3+|1+p|=12 -3 = -3 -------------- Please complete this work.
I seemed to have written the equation wrong but I seem to have gotten the right answer. Sorry about that.
i am sorry i dont know what to do first
This can help you understand :) http://www.coolmath.com/algebra/18-absolute-value-equations-inequalities/02-solving-absolute-value-equations-01
Given 3+|1+p|=12 -3 = -3 -------------- please begin by subtracting 3 from 3. Type out your result.
3 - 3 ----- ??
that is 0
True, so then you have |1+p| on the left side. What have you on the right side?
subtract 3
Yes, subtract 3 from 12. Your result?
-9
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