Medal Q10 http://prnt.sc/cisg8s
@mathstudent55 @mathmale @ltrout
compute \[4^{-3}*4^2~first.\]
Review rules of exponentiation. 4^a*4^b =4^(a+b)
Adapt this rule to fit the current situation.
what is 4^-3?
Your 4^-3, better written as \[4^{-3},\] is equal to \[\frac{ 1 }{ 4^3 }. \]
What is 4^3?
64?
yes.
But in the numerator of the given problem, you have \[4^{-3}4^2\] Please reduce this.
Combine the 2 exponents, -3 and +2. Write your result here:
3882 @mathmale
@mathmale @WHEREISTHEFLOOR @Elsa213 @TheSmartOne @AloneS
what is the problem it looks like mathmale solved it
Go back and look at the original problem, please. I asked that you simplify:\[4^{-3}4^2\]
using the appropriate rule of exponentiation.
Here are 2 such rules:\[a^b a^c=a ^{b+c}\]
\[e^c e ^{-d}=e ^{c-d}\]
i dont get that
8^-1?
As before, there are "rules of exponentation" that you MUST learn, study and apply to problems. It's not a matter of "I don't get that;" you have to learn this material and remember it for later application.
\[4^{-3}4^2\] reduces to \[4^{-3+2}\]
Note that we kept the base 4 here; do NOT change the base. Again, follow the rules of exponentiation.
ok
Now, please reduce / simplify:\[4^{-3+2}\]
What is -3+2?
@mathmale -1
Right. Now, please evaluate / simplify\[4^{-1}\]
well since 4^1 is 1 would this be -1?
Milo, it appears you'll need to read up on "exponentiation." That \[4^{-1}\]
consists of the base, 4, and the exponent, -1. The pertinent rule is \[a ^{-1}=\frac{ 1 }{ a^1 }=\frac{ 1 }{ a }\]
You must know and understand this rule.
Using this rule, find the value of\[4^{-1}\]
Note that this is not a multiplication problem; it's an exponentiation one.
\[\frac{ 1 }{ 4^1 }\]
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