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Mathematics 8 Online
OpenStudy (milo123):

Medal Q10 http://prnt.sc/cisg8s

OpenStudy (milo123):

@mathstudent55 @mathmale @ltrout

OpenStudy (mathmale):

compute \[4^{-3}*4^2~first.\]

OpenStudy (mathmale):

Review rules of exponentiation. 4^a*4^b =4^(a+b)

OpenStudy (mathmale):

Adapt this rule to fit the current situation.

OpenStudy (milo123):

what is 4^-3?

OpenStudy (mathmale):

Your 4^-3, better written as \[4^{-3},\] is equal to \[\frac{ 1 }{ 4^3 }. \]

OpenStudy (mathmale):

What is 4^3?

OpenStudy (milo123):

64?

OpenStudy (mathmale):

yes.

OpenStudy (mathmale):

But in the numerator of the given problem, you have \[4^{-3}4^2\] Please reduce this.

OpenStudy (mathmale):

Combine the 2 exponents, -3 and +2. Write your result here:

OpenStudy (milo123):

3882 @mathmale

OpenStudy (milo123):

@mathmale @WHEREISTHEFLOOR @Elsa213 @TheSmartOne @AloneS

OpenStudy (whereisthefloor):

what is the problem it looks like mathmale solved it

OpenStudy (mathmale):

Go back and look at the original problem, please. I asked that you simplify:\[4^{-3}4^2\]

OpenStudy (mathmale):

using the appropriate rule of exponentiation.

OpenStudy (mathmale):

Here are 2 such rules:\[a^b a^c=a ^{b+c}\]

OpenStudy (mathmale):

\[e^c e ^{-d}=e ^{c-d}\]

OpenStudy (milo123):

i dont get that

OpenStudy (milo123):

8^-1?

OpenStudy (mathmale):

As before, there are "rules of exponentation" that you MUST learn, study and apply to problems. It's not a matter of "I don't get that;" you have to learn this material and remember it for later application.

OpenStudy (mathmale):

\[4^{-3}4^2\] reduces to \[4^{-3+2}\]

OpenStudy (mathmale):

Note that we kept the base 4 here; do NOT change the base. Again, follow the rules of exponentiation.

OpenStudy (milo123):

ok

OpenStudy (mathmale):

Now, please reduce / simplify:\[4^{-3+2}\]

OpenStudy (mathmale):

What is -3+2?

OpenStudy (milo123):

@mathmale -1

OpenStudy (mathmale):

Right. Now, please evaluate / simplify\[4^{-1}\]

OpenStudy (milo123):

well since 4^1 is 1 would this be -1?

OpenStudy (mathmale):

Milo, it appears you'll need to read up on "exponentiation." That \[4^{-1}\]

OpenStudy (mathmale):

consists of the base, 4, and the exponent, -1. The pertinent rule is \[a ^{-1}=\frac{ 1 }{ a^1 }=\frac{ 1 }{ a }\]

OpenStudy (mathmale):

You must know and understand this rule.

OpenStudy (mathmale):

Using this rule, find the value of\[4^{-1}\]

OpenStudy (mathmale):

Note that this is not a multiplication problem; it's an exponentiation one.

OpenStudy (milo123):

\[\frac{ 1 }{ 4^1 }\]

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