Question

Hi guys, please help me
s=2πr^2+2πrh solve for h

Answer 1

@YanaSidlinskiy

Answer 2

\[S = 2\pi r^2 + 2\pi rh\] is that the question?

Answer 3

yup @Will.H

Answer 4

can you help? @Will.H

Answer 5

yes am just trying to figure a way to remove r^2

Answer 6

oh okay take your time lol @Will.H thank you in advance i really appreciate it :))

Answer 7

i made a mistake 1 moment lol i am too sleepy
So i don't know where i got that 2 from here's the correct solve
\[S = 2\pi r^2 + 2\pi rh\]
\[S - 2\pi r^2 = 2\pi rh\]
\[\frac{ S - 2\pi r^2 }{ 2\pi r } = h\]

Answer 8

Sorry for the confusion

Answer 9

Its okay don't worry about it :) @Will.H

Answer 10

There's another solution if you ever heard about factoring
here it is
\[S = 2\pi r^2 + 2\pi rh\]
There's a GCF in the right side of 2pi r
\[S = 2\pi r(r + h)\]
Now divide both sides by 2pi r
\[\frac{ S }{ 2\pi r } = r + h\] and now we may subtract r from both sides to isolate h
\[\frac{ S }{ 2\pi r } - r = h\]
Personally i would prefer this way

Answer 11

@Will.H this is very very nice great job really

Answer 12

Thank you Jhony :) @jhonyy9

Answer 13

np

welcome

Answer 14

You could also use $$C=2\pi r$$ to make it look even simpler.