If the operation (a mod b) is the remainder of division operation by b, calculate (7^7.777.777 mod 100) + (5^5.555.555 mod 10)? The answer is 12. Pls tell me step by step how to get its number.
@mathmate @mathmale @skullpatrol @RadEn @princeharryyy
Um, what grade is this? xD
arithmetic for computer science XD
Uhh
yup
what are dots in 7777777
It just takes a little patience! Make a table, I'll start witht he first 3 entries, and will let you finish it until you find a pattern. n 7^n mod(7^n,100) 1 7 7 2 49 49 3 343 43 4 ... If the pattern has a period of k, then 7^7777777\(\equiv\)7^(7777777 mod k), the latter of which can be calculated using a calculator. You can do the same with 5^5555555 mod 10. I have verified the answer, which is indeed 12.
I'm sorry. Dots is not decimal symbol.
okay
it can be done manually.
amd yes the answer is right.
it is 12
the pattern will recur every 4x. Then?
5 to power anything will leave 5 in the end... see, 5^1 =5 5^2 = 25 5^3 = 125 and so on. and because we have to find the mod we are concerned with last digit of 5^ whatever. So the remainder of second part would be 5. Right?
I know how to find the remainder. So what?
you are looking for remainder in this question or are you not?
I mean after find the remainder. What we are going to do
So you found k=4, Next step is to use 7^7777777 mod 100 ≡7^(7777777 mod k) mod 100
we are going to find the remainder for the first one. LOL. We have already done the second part.
when u divide the power 7777777 you would be left with only 1 power every thing else qould be contained in the division by 4.
Owhh... I get it now
@Kevin You need to find the remainder of the each of 7^7777777 mod 100 and 5^5555555 mod 10. After that, the sum should equal 12.
It would be 7^1 mod 100 + 5^1 mod 100 ?
7^7777777 = 7^1
7^1 mod 100 + 5^1 mod 10 = 7 +5 =12
Sorry, that's what I mean 7^1 mod 100 + 5^1 mod 10
Thx guys
yes it's right.@Kevin
I don't know whom I give the medal since both of you help me. lol
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