Question

Given the following information, determine the Keq for the following reaction: 2H2S (g) 2-way arrow 2H2 (g) + S2 (g)

Substance

Concentration (M) at equilibrium

H2S

0.15

H2

0.010

S2

0.051



2.3 x 10-4

8.8 x 103

3.4 x 10-3

2.9 x 10-2

Answer 1

Here the attached file is better xD.

Answer 2

is it about equilibrium constant?

Answer 3

Pretty sure it's 3. :D I used a process too complicated and it's too much of a mess to type it on here but i'm sure it's 3

Answer 4

Okay

Answer 5

Well ik you get alot of stuff wrong, so please show me your work.

Answer 6

That would be
(0.010^2 + 0.051) / 0.15^2
isn't?

Answer 7

What is it Kevin? I don't understand.

Answer 8

The question is about equilibrium reaction right?
what is Keq?
I don't use that symbol

Answer 9

dammit if u don't believe me get someone else. I already tried typing it and I didn't even get a millionth of the way

Answer 10

1. Yep
2. The "K" in Keq stands for "Constant". The "eq" means that the reaction is at equilibrium. Very roughly, Keq tells you the ratio of Products/Reactants for a given reaction at equilibrium.

Answer 11

its actually \[K _{eq}\] is the technical symbol

Answer 12

and Keq = [Products] / [Reactants]