Question

Luggage is transported from one location to another in an airport by a conveyor belt. At a certain location, the belt moves down an incline that makes an angle of 2.2° with the horizontal. Assume that with such a slight angle there is no slipping of the luggage. Determine the frictional force, including sign, by the belt on a box weighing 62 N when the box is on the inclined portion of the belt and the belt speed is (a) 0 and constant, (b)0.65 m/s and constant, (c)0.65 m/s and increasing at a rate of 0.22 m/s2, (d)0.65 m/s and decreasing at a rate of 0.22 m/s2, and (e)0.65 m/s and increasing a

Answer 1

this is the force diagram for the stationary luggage
Resolving forces along the belt
Friction F = X

where X is the component down the slope of the weight of the luggage (62N)

Answer 2

find the vakue of X using trigonometry

sorry gtg

Answer 3

What's the next step? :(