A chemist has a 55.0 mL of a 1.50 M solution of NaOH available. Yet he needs 1.00 M solution. How many mL of 1.00 M can he make if he uses all the 55.0 mL?

Remember: C1 X V1 = C2 X V2

A. 82.5 mL

B. 40.0 mL

C. 12.1 mL

D. 0.0825 mL

Please explain. Thank you!

Question

A chemist has a 55.0 mL of a 1.50 M solution of NaOH available. Yet he needs 1.00 M solution. How many mL of 1.00 M can he make if he uses all the 55.0 mL?

Remember: C1 X V1 = C2 X V2

A. 82.5 mL

B. 40.0 mL

C. 12.1 mL

D. 0.0825 mL

Please explain. Thank you!

kj4uts · Answer

I guess it is set up like this: 1.50 M X V1 = 1.00 M X 55 mL?

abhisar · Answer

$\sf1.50 \times 55 mL = 1.00 \times V_2$

abhisar · Answer

Got it?

kj4uts · Answer

Ok is see so then the 1.50 X 55 = 82.5 = 1.00 X V2. How do I solve that part?

abhisar · Answer

$\sf \Rightarrow V_2=\frac{82.5}{1}=82.5$

kj4uts · Answer

Oh I see so it is just 82.5 then.

abhisar · Answer

Yeppers!

kj4uts · Answer

Just curious does the 82.5 come out as mL?

abhisar · Answer

Obviously. You too 55.0 mL so the other volume will also be in mL. Take it as 0.055 L and the volume will come in L

abhisar · Answer

Cool?

kj4uts · Answer

Gotcha, thanks for your time and help!