Solve (28/x) - (7/x^2) = 7
like a first step what will be the common denominator ?
Um I'm not sure.
for x and x^2 what is the GCF ?
x?
sorry not is this the right question for common denominator
the great common divisor ?
Sorry I don't think I know
why not this is very easy for x^2 is x^2 yes ? bc. x^2 /x^2 = 1 and for x is too x^2 bc. x^2 /x = x ok. ?
Okay
so and in this way you get that the common denominator is x^2
Yes
so than x^2 is the common denominator with what will need multiplie the first fraction ?
x?
yes sure
and on the other side the 7 ?
So the first fraction multiplied would be 28x/x^2 and then the 7 would be 7x?
no for 7x so than the common denominator is x^2 and the 7 on the right side has the denominator 1 so than with what will be necessary multiplie the 7 ?
x^2
yes sure exactly this is easy and you know it just more courage please ok. ?
so now please make what you write above
28x/x^2 - 7/x^2 = 7/x^2 I'm confused about the 7/x^2 part though
no on the right side multiplie the 7 not just divide by x^2
7x^2
yes so how will be ?
28x/x^2 - 7/x^2 = 7x^2
I think the easy thing to do is multiply every term by x^2 and that will eliminate all denominators' then looking at things divide every term by 7 then I'd expect it's general quadratic formula for the solutions.
like this \[\frac{28}{x} \times x^2 - \frac{7}{x^2} \times x^2 = 7 \times x^2\]
Ah, okay that makes sense.
And then after that would I just use the quadratic formula to solve?
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