3 + sq rt of z-11 = - sq rt of z+4

Question

3 + sq rt of z-11   = - sq rt of z+4

leenathan · Answer

sphott51 · Answer

the negative is on the outside of the sq rt so i'm not entirely sure what to do with it.

jhonyy9 · Answer

so there are 

3 +sqrt(z-11) = -sqrt(z+4)   yes ?

sphott51 · Answer

yes

jhonyy9 · Answer

ok

so like a first step square both sides so what will get ?

sphott51 · Answer

3 +z-11 = (- ? ) z+4

jhonyy9 · Answer

no

than square both sides will be 

(3 + sqrt(z-11) )^2 = (- sqrt(z+4) )^2

sphott51 · Answer

oh so no negative?

jhonyy9 · Answer

on the lrft part use formula of (a+b)^2 = ?

jhonyy9 · Answer

on the left part

sphott51 · Answer

9 + z-11 = z+4

jhonyy9 · Answer

on the left part not is right 

(a+b)^2 = a^2 +2ab +b^2

sphott51 · Answer

Erm I basically just crossed out the square and square root  3^2 is 9

jhonyy9 · Answer

but so not is correct bc, you need square the all right side with these two terms 
and so will need using this formula of (a+b)^2

jhonyy9 · Answer

sory left side not right side

sphott51 · Answer

Okay, sorry i'm not getting it?

jhonyy9 · Answer

but i ve wrote there above all what you need to use

sphott51 · Answer

So I literally have to do the square root part twice?

jhonyy9 · Answer

on the left side use formula of (a+b)^2 = a^2 +2ab +b^2

with a=3 and b=sqrt(z-11)

sphott51 · Answer

$$\sqrt{z-11}^2$$

sphott51 · Answer

I don't know how to do this