Question

Simplify the expression. (I'm having trouble with what to do with the denominator.)

Answer 1

Take (x+6) common from numerator

Answer 2

\(3x(x+6)-6x^2 \over (x+6)^5\)

Answer 3

$$\Huge \dfrac{3x(x+6)^4 - x^2 (6)(x+6)^3}{(x+6)^8}$$

$$\Huge = \dfrac{[3x(x+6)- x^2 (6)](x+6)^3}{(x+6)^8}$$

$$\Huge = \dfrac{[3x(x+6)- x^2 (6)](x+6)^3}{(x+6)^5 • (x+6)^3}$$

$$\Huge = \dfrac{[3x(x+6)- x^2 (6)]\cancel{(x+6)^3}}{(x+6)^5• \cancel{(x+6)^3}}$$

$$\Huge = \dfrac{3x(x+6)- x^2 (6)}{(x+6)^5}$$

$$\Huge = \dfrac{3x^2 +18x - 6x^2}{(x+6)^5}$$

$$\Huge = \dfrac{-3x^2 + 18x}{(x+6)^5}$$

$$\Huge x \neq -6$$