Suppose a normal distribution has a mean of 16 and a standard deviation of 4. A value of 26 is how many standard deviations away from the mean?
What is the actual value difference betwen 26 and 16? then divide that by the SD (4)
tgis is given by the standard normal variable z \[z = (x - \mu) / \]
so it'd be 2.5 right?
Yes = it is the z score of 26 =2.5
z = (26 - 16) / 4
is the "z" in your equation the same thing as a z-score or are they different things? @welshfella
it is the z-score
Suppose the test scores of students in a class are normally distributed with a mean of 92 and a standard deviation of 3. What is the z-score for a student that scored 86 on a test? so for this, it'd be z = (86 - 92) / 3 right?
Yes - that's right Looks like you know how to do z scores now! :-)
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