Question

What is the percent yield for the reaction, CaCO3 arrow CaO + CO2 , if 13.1 grams of CaO is actually produced when 24.8 grams of CaCO3 is heated? Show all equation setup work and the final answer.

Answer 1

@Will.H

Answer 2

@Will.H
@danieldjpon3, I am still asking because I don't get it yet :(

Answer 3

ye me 2

Answer 4

@Will.H, can you help?

Answer 5

yes,
Percentage yield= actual yield (13.10)/theoretical yield x 100
just a simple formula will get you the answer

Answer 6

CaCO3 → CaO + CO2

(24.8 g CaCO3) / (100.0875 g CaCO3/mol) x (1 mol CaO / 1 mol CaCO3) x (56.0774 g CaO/mol) =
13.895 g CaO in theory

(13.1 g) / (13.895 g) = 0.943 = 94.3% yield

Answer 7

is that good?

Answer 8

I got BasketBall practice in like 3 hours from now so ye

Answer 9

@NvidiaIntely is that good

Answer 10

Yeah thanks!