Question

Find the derivative: y = 2sinxtanx
Is it: 2cosxtanx + sec^2(x)sinx
Anyone mind checking for me?

Answer 1

did you miss the 2 in the 2nd term?

Answer 2

It's supposed to be 2sinx because of the original?

Answer 3

yes

Answer 4

So, it would be 2cos(x)tan(x) + sec^2(x)2sin(x), yes?

Answer 5

2cos(x)tan(x) + 2sec^2(x)sin(x) would be convenient

Answer 6

right
which is same as
2cos(x)tan(x) + 2sec^2(x)sin(x)

although this can be simplied further, but i don't think thats required.

Answer 7

Or would the 2 be throughout like this: 2cos(x)tan(x) + 2sec^2(x)sin(x)? (sorry my internet dropped)

Answer 8

Oh okay, I got it, thank you so much.

Answer 9

welcome ^_^