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Mathematics 21 Online
OpenStudy (bringmetherain):

1) The mean hourly salary of the 10 employees at a fast-food restaurant is $8.25. One of the employees earning $6.50 an hour leaves the company, and another employee is hired at $5.50 an hour. What is the new mean salary of the employees? 2) Rachel flips a coin 150 times and finds that the probability of the coin landing heads up is 1/2. Rachel wants to flip the same coin 15 more times. On the first 14 flips, the coin lands heads up. Which statement BEST describes the probability of the coin landing heads up on the 15th flip? The probability of the coin landing heads up is 1/2 The probability of the coin landing heads up is 1/15 The probability of the coin landing heads up is 14/15 The probability of the coin landing heads up is 1.

OpenStudy (mathstudent55):

Do you know how to calculate the mean of a set of data?

OpenStudy (bringmetherain):

Yes, you add all the values together and then divide it by the number of values there are. @mathstudent55

OpenStudy (mathstudent55):

Great. There are 10 employees. They have a mean salary of $8.25. How was that mean calculated?

OpenStudy (bringmetherain):

They added together the salary of the 10 employees?

OpenStudy (mathstudent55):

Correct. Then they divided the total by 10. You know the mean, and you know there are 10 employees. What was the total of the salaries?

OpenStudy (bringmetherain):

82.5

OpenStudy (bringmetherain):

Since 82.5/10 would equal $8.25

OpenStudy (mathstudent55):

Good. Now you need to find the new total using the new salaray instead of the old one.

OpenStudy (mathstudent55):

new total of salaries = $82.50 - $6.50 + $5.50 ok?

OpenStudy (mathstudent55):

Then divide the new total by the number of employees to find the new average salary.

OpenStudy (bringmetherain):

The new salary would be $8.15 right? @mathstudent55

OpenStudy (mathstudent55):

Correct. Good job1

OpenStudy (bringmetherain):

Thank you! @mathstudent55

OpenStudy (mathstudent55):

Do you need help on the second question? If so, you need to complete it. Info is missing from it as well as the options.

OpenStudy (bringmetherain):

Yes I do, and hold on I'll fix it right now

OpenStudy (mathstudent55):

You're welcome.

OpenStudy (mathstudent55):

2) Rachel flips a coin 150 times and finds that the probability of the coin landing heads up is \(\bf \color{red}{missing~ fraction}\). Rachel wants to flip the same coin 15 more times. On the first 14 flips, the coin lands heads up. Which statement BEST describes the probability of the coin landing heads up on the 15th flip?

OpenStudy (bringmetherain):

The missing fraction is 1/2, sorry!

OpenStudy (mathstudent55):

Please don't delete your first question. These questions stay on OS for others to see. Since your first question is answered above, it can be a good help to someone else who needs to answer it.

OpenStudy (bringmetherain):

Yes, I understand that. But I wasn't able to fit in the the answer choices so I deleted it, I should've just commented them but I wasn't thinking.

OpenStudy (mathstudent55):

Ok. The coin has a 1/2 probability of landing heads up and 1/2 probability of landing on tails up. This means that in the long run, after many, many flips you should get the same number of heads and tails.

OpenStudy (mathstudent55):

In other words, even if at times you get a few or even many heads or tails in a row, the results will even up eventually after many, many tosses.

OpenStudy (bringmetherain):

So it'll still be 1/2 of a probability?

OpenStudy (mathstudent55):

By flipping the coin 150 times she knows the probability of landing heads or tails is still 1/2 for any single coin toss.

OpenStudy (mathstudent55):

You are correct.

OpenStudy (mathstudent55):

Good job again.

OpenStudy (bringmetherain):

Again, thank you for all your help (:

OpenStudy (mathstudent55):

You were able to re-post the first question? Great, well done. You're welcome.

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