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Chemistry 8 Online
OpenStudy (chelselyse):

Which of the following aqueous liquids will have the lowest freezing point? 0.5 m C12H22O11 (sucrose) 0.5 m Ca(NO3)2 0.5 m NiSO4 0.5 m Li3PO4 pure water

OpenStudy (jiteshmeghwal9):

Higher the number of solute particles lower will be the freezing point

OpenStudy (jiteshmeghwal9):

(1) sucrose do not dissociate in water thus number of sucrose particles in 1 kg water is 0.5 \(N_A\) particles

OpenStudy (jiteshmeghwal9):

(2) calcium nitrate dissociate into \(Ca^{+2}\) and \(2NO_3^{-}\). Total number of solute particles in the solution becomes 0.5*3* \(N_A\)

OpenStudy (jiteshmeghwal9):

Similarly Nickel sulphate dissociate into \(Ni^{+2}\) and \(SO_4^{-2}\). Total number of solute particles becomes 0.5*2* \(N_A\)

OpenStudy (jiteshmeghwal9):

Lithium phosphate dissociate in \(3Li^{+}\) and \(PO_4^{-3}\) ions. Total number of solute particles becomes 0.5*4* \(N_A\)

OpenStudy (jiteshmeghwal9):

Freezing point of pure water is 0 degree Centigrade which on dissolution of solute falls

OpenStudy (jiteshmeghwal9):

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