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Mathematics 14 Online
OpenStudy (amy2012):

How do you find the slope and y intersect of a function. problem is attached!

OpenStudy (amy2012):

OpenStudy (kittiwitti1):

first find the slope. given two points \((x_{1},y_{1})\) and \((x_{2},y_{2})\)\[\Large{m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}}\]next, the point-slope formula, which is \[y-y_{1}=m(x-x_{1})\]In this formula you can use either of the points you were given. Input the respective values, then simplify so you get the equation form below:\[y=mx+b\]\(b\) is the y-intercept.

OpenStudy (kittiwitti1):

I have to go now, hope that was helpful! good luck :)

OpenStudy (danjs):

you get it?

OpenStudy (amy2012):

@DanJS I understand how to do y−y 1 =m(x−x 1 ) ...I don't know what points listed go where.

OpenStudy (danjs):

They give you two inputs to the function y=f(x), x=5 and x=10 f(5) = -6 and f(10) = -1 Those are the points (5 , -6) and (10 , -1)

OpenStudy (danjs):

You calculate the slope of a line through those 2 points from difference in Y over Difference in X coordinates...rise/run, the order you call point 1 or 2 doesnt matter, it comes out the same.. \[m=\frac{ -6 - (-1) }{ 5 - 10 } = \frac{ -5 }{ -5 }=1 \] same as \[m=\frac{ -1 - (-6) }{ 10 - 5 } =\frac{ 5 }{ 5 }=1\]

OpenStudy (danjs):

Also, for the line equation, \[y-y_{1}=m(x-x_{1})\] you can use either point for (x1,y1), just has to be some point on the line.

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