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Mathematics 8 Online
OpenStudy (quickstudent):

Can someone please help me? Find the value of x.

OpenStudy (quickstudent):

OpenStudy (quickstudent):

It's been a long time, I really don't remember how to do this. Can somebody walk me through?

OpenStudy (will.h):

are you familiar with the trigonometric functions?

OpenStudy (mathstudent55):

You can also use the ratios of the lengths of the sides of a 45-45-90 triangle.

OpenStudy (mathstudent55):

Also, Pythagoras theorem.

OpenStudy (will.h):

you can use the Cos formula Cos = Adjacent/hypotenuse Cos 45 = 12/x Solve for x and thats all

OpenStudy (quickstudent):

@mathstudent55 let me know of that method because I haven't really learned about the trig functions yet.

OpenStudy (mathstudent55):

What is angle measure a? |dw:1474375758262:dw|

OpenStudy (quickstudent):

45 degrees

OpenStudy (mathstudent55):

Let's use the Pythagoras theorem \(a^2 + b^2 = c^2\) You know one angle is a right angle with measure 90 deg. The other given angle has measure 45 deg. What is the measure of the third angle?

OpenStudy (mathstudent55):

Good. In a triangle, if 2 angles are congruent, then the sides opposite those angles are congruent.

OpenStudy (will.h):

\[\cos 45 = \frac{ 12 }{ x }\] Cross multiply \[12 = \cos 45 * x\] divide both sides by cos 45 \[12\sqrt{2} = x\]

OpenStudy (mathstudent55):

|dw:1474375963866:dw|

OpenStudy (mathstudent55):

What is side length b?

OpenStudy (quickstudent):

So that should be 12 too, right?

OpenStudy (mathstudent55):

Correct. |dw:1474376056170:dw|

OpenStudy (quickstudent):

Oh so than I can use pythagorean theorem to solve for c now.

OpenStudy (mathstudent55):

Now we can use the Pythagoras theorem with legs of length 12 and unknown hypotenuse. The legs are a and b. The hypotenuse is c. \(a^2 + b^2 = c^2\) \(12^2 + 12^2 = c^2\) Can you solve for c?

OpenStudy (will.h):

That's also a good way

OpenStudy (quickstudent):

I got an unending decimal, but I rounded it to 16.97

OpenStudy (will.h):

or you can keep it as \[12\sqrt{2}\]

OpenStudy (quickstudent):

Oh yeah, that's right. Thanks:)

OpenStudy (will.h):

yw:)

OpenStudy (mathstudent55):

These problems should be answered with a number in radical form. This way the answer is exact. \(12^2 + 12^2 = c^2\) \(144 + 144 = c^2\) \(c^2 = 288\) \(c = \sqrt{288} \) \(c = \sqrt {144 \times 2}\) \(c = \sqrt{144} \times \sqrt 2\) \(c = 12\sqrt 2\) In this problem the hypotenuse is labeled x, so the answer is: \(x = 12\sqrt{2}\)

OpenStudy (mathstudent55):

You are correct.

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