Can someone please help me? Find the value of x.
It's been a long time, I really don't remember how to do this. Can somebody walk me through?
are you familiar with the trigonometric functions?
You can also use the ratios of the lengths of the sides of a 45-45-90 triangle.
Also, Pythagoras theorem.
you can use the Cos formula Cos = Adjacent/hypotenuse Cos 45 = 12/x Solve for x and thats all
@mathstudent55 let me know of that method because I haven't really learned about the trig functions yet.
What is angle measure a? |dw:1474375758262:dw|
45 degrees
Let's use the Pythagoras theorem \(a^2 + b^2 = c^2\) You know one angle is a right angle with measure 90 deg. The other given angle has measure 45 deg. What is the measure of the third angle?
Good. In a triangle, if 2 angles are congruent, then the sides opposite those angles are congruent.
\[\cos 45 = \frac{ 12 }{ x }\] Cross multiply \[12 = \cos 45 * x\] divide both sides by cos 45 \[12\sqrt{2} = x\]
|dw:1474375963866:dw|
What is side length b?
So that should be 12 too, right?
Correct. |dw:1474376056170:dw|
Oh so than I can use pythagorean theorem to solve for c now.
Now we can use the Pythagoras theorem with legs of length 12 and unknown hypotenuse. The legs are a and b. The hypotenuse is c. \(a^2 + b^2 = c^2\) \(12^2 + 12^2 = c^2\) Can you solve for c?
That's also a good way
I got an unending decimal, but I rounded it to 16.97
or you can keep it as \[12\sqrt{2}\]
Oh yeah, that's right. Thanks:)
yw:)
These problems should be answered with a number in radical form. This way the answer is exact. \(12^2 + 12^2 = c^2\) \(144 + 144 = c^2\) \(c^2 = 288\) \(c = \sqrt{288} \) \(c = \sqrt {144 \times 2}\) \(c = \sqrt{144} \times \sqrt 2\) \(c = 12\sqrt 2\) In this problem the hypotenuse is labeled x, so the answer is: \(x = 12\sqrt{2}\)
You are correct.
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