Question

partial fractions

Answer 1

\[\int\limits_{}^{} \frac{ 4x }{ x^3+x^2+x+1 }\]

Answer 2

@agent0smith

Answer 3

So you must integrate and that is what you are trying to find I assume?

Answer 4

i was thinking of factoring the bottom

Answer 5

Well when integrating you can change what you were given into\[\int\limits_{}^{}4x - \int\limits_{}^{}x^3+x^2+x+1\] so dividing becomes subtraction, do you see?

Answer 6

First you gotta factor the denom
\[\large \frac{ 4x }{ x^3+x^2+x+1 } =\frac{ 4x }{ x^2(x+1)+1(x+1) }=\]factor by grouping\[\large \frac{ 4x }{( x^2+1)(x+1) }\]

Answer 7

so how come it aint\[(x+1)^2\]

Answer 8

Because you can't factor x^2+1 at all..

Now partial fractions\[\large \frac{ 4x }{( x^2+1)(x+1) }= \frac{ Ax + B }{ x^2+1}+\frac{ C }{ x+1}\]

Answer 9

ohh i see. its basically factoring what you are seeing ...

Answer 10

Yeah. Gurl I can finish later or make you a video, prob easier

Answer 11

iight x'd :D

Answer 12

iight i'll make one