Question

In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability that the family has 0, 1, or 2 girls.

Answer 1

(a) Draw a tree diagram showing the possibilities for each outcome.
(b) create the binomial distribution table for P (X).

Answer 2

@agent0smith

Answer 3

multiply probabilities along branches

Answer 4

@agent0smith Ok, here is my possible outcomes (probability when Multiplied):

BB- .2704
BG- .2496
GB- .2496
GG- .2304

NOw, how do I make it into a binomial distribution table for P(X)?

Answer 5

Remember X is the number of girls.

I guess just make the table showing probability for X= 0, 1, 2

Answer 6

I'd google "binomial distribution table" since i'm not sure how it's supposed to look...

Answer 7

But how do I know which of the numbers I multiplied are 0, 1, and 2? And it's supposed to look like this (just an example:

Answer 8

@agent0smith

Answer 9

@agent0smith

Answer 10

@brainzonly @kmd284

Answer 11

@Benji

Answer 12

Ok here is what I got

Answer 13

Now, I added both the BG and GB for the 1 girl in the family, not sure if that's right or not