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Mathematics 20 Online
OpenStudy (iwanttogotostanford):

Ple

OpenStudy (iwanttogotostanford):

@Kevin

OpenStudy (iwanttogotostanford):

@Visarika23

OpenStudy (iwanttogotostanford):

@Kevin

OpenStudy (kevin):

I'm confused since it has 2 pairs One of the pairs would be like this : r = sqrt(4^2 + (-4)^2) = 4sqrt(2) cos alpha = x/ r = 4/4sqrt(2) = 1/2 sqrt(2) alpha = arc cos 1/sqrt(2) = 45 degree

OpenStudy (kevin):

One of two pairs --> (4 square root of 2, 45°)

OpenStudy (iwanttogotostanford):

ah so it would be A?

OpenStudy (kevin):

maybe, I don't know how to get (-4 square root of 2, 225°)

OpenStudy (iwanttogotostanford):

? any idea

OpenStudy (kevin):

wait

OpenStudy (iwanttogotostanford):

ok thnx

OpenStudy (kevin):

Hey.. about the first question.. maybe it's B

OpenStudy (kevin):

What's ur answer?

OpenStudy (iwanttogotostanford):

so instead of it being A you're thinking the answer to the first one is B?

OpenStudy (iwanttogotostanford):

and for the second one my answer that I got was this: (5, pi/3 + 2npi) or (-5 , pi/3, +(2n+1)pi)

OpenStudy (kevin):

r = sqrt(4^2 + (-4)^2) = 4sqrt(2) tan alpha = y/x = -4/4 = -1 alpha = arc tan -1 = 135 degree

OpenStudy (kevin):

r = sqrt(4^2 + (-4)^2) = 4sqrt(2) OR -4 sqrt(2) tan alpha = y/x = -4/4 = -1 alpha = arc tan -1 = 135 degree OR 315 degree The answer is B

OpenStudy (kevin):

can u explain to me your about your answer on the second question?

OpenStudy (iwanttogotostanford):

ah ok! and I worked it out in class with my tutor/.... and got that

OpenStudy (kevin):

what is it? your first question?

OpenStudy (kevin):

Sorry I don't understand about your second question

OpenStudy (iwanttogotostanford):

no the second!

OpenStudy (iwanttogotostanford):

@Kevin

OpenStudy (iwanttogotostanford):

@HolsterEmission

OpenStudy (kevin):

How did you get your answer? and what is 'n' ?

OpenStudy (iwanttogotostanford):

@jhonyy9 @retirEEd @Teddyiswatshecallsme am i right?

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