Chemistry question (cross posting for visibility, sorry):
Given the following analytical data calculate the chemical formula for the two minerals and hence identify the minerals. Values given are in weight percent. A. Cu=63.3, Fe=11.1, S=25.6 B. SiO\(_{2}\)=38.0, Al\(_{2}\)O\(_{3}\)=21.5, FeO=26.6, MgO=6.3, MnO=7.6 Calculate b) in terms of a formula with 12 oxygens.
Click on the "Mathematics Section" and search up "Chemistry Section" and you got it! Please close this! Thank you for listening! :D
It's for mineralogy
We are dealing with oxides and such
@mathmate your writing really long
@legomyego180 For cross visibility, post in the appropriate section, then post a \(link\) in other sections in order to group all answers and discussions in a single post. Hint: Divide mass percentages by respective atomic mass to get ratio of number of atoms of the given compound. Then divide by the smallest value (or smallest difference) to get whole number ratios. Next, figure out minerals that contain those elements in the resulting proportion. Example: Cu: 50%, S:50% Divide by atomic mass: 50/63.55=.787 50/32=1.56 Divide by smallest value (0.787) or smallest difference (1.56-.787=.773) Cu: .787/.773=1 S=1.56/.773=2 So mineral is CuS2 (or multiple) Look up CuS2 to get possible name of mineral = Villamaninite
Thanks Mathmate. I will do that next time. Give me a minute to play around with what you said and Ill see what I come up with...
Sorry but I have to go, but I will check back as soon as I can.
Not a problem
@Legomyego180 Have you found the minerals?
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