Question

Given the following chemical equation, how many grams of carbon monoxide gas are produced when 50.0 grams of silicon dioxide reacts with 36.0 grams of carbon?
SiO2 (s) + 3C (s) arrow SiC (s) + 2CO (g)

56.0 grams

168 grams

46.6 grams

67.3 grams

Answer 1

@ScribblePikachu @Kevin @Google @Will.H

Answer 2

mk hold on a min

Answer 3

Okay.

Answer 4

46.6 g


Work out how much CO would be formed from all of each reagent individually. The one that produces the least product is the limiting reagent and the amount it produces is the expected tield.

SiO2
(50.0 g / 60.09 g/mol) x (2 mol CO / 1 mol SiO2) x 28.01 g/mol = 46.6 g

Carbon
(36.0 g / 12.01 g/mol) x (2 mol CO / 3 mol C) x 28.01 g/mol = 56.0 g

The amount of SiO2 provided yields the least product, thus SiO2 is the limiting reagent and
the amount of product = 46.6 g

Answer 5

Thank yoou.

Answer 6

Th a n k s !

Answer 7

np