Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.)

1.40 x 101 L

1.84 x 10-2 L

1.17 x 102 L

1.54 x 10-1 L

Question

Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.)
		
1.40 x 101 L
		
1.84 x 10-2 L
		
1.17 x 102 L
		
1.54 x 10-1 L

helpz-q · Answer

So first tell me what you think it is... explain your thoughts as well as opinions

helpz-q · Answer

And actually i am a 9th grade teacher and i have been teaching my class this for a while now

jiteshmeghwal9 · Answer

p=pressure=792/760 atm
n=4.8
T=37+273 'kelvin
R=0.0821

jiteshmeghwal9 · Answer

v=nRT/P

nvidiaintely · Answer

I think its option C.

francesca_marie · Answer

It's all in the equation: 

PV = nRT 
You know the following: 
P = 792 torr 
T = 310 degrees K (you must convert to degrees K) 
n = 4.8 moles 

So rearrange to solve for V 

V = nRT/V 

Now, convert the P into atm (divide 790 by 760) and plug in the value of R to get your volume, in L. 

or 
choose a value for R that is in units to L-torr/deg mol (this is 62.364) and solve it that way. 

In either case, I get 118, which appears to be answer C

jiteshmeghwal9 · Answer

yes u  r correct @NvidiaIntely

nvidiaintely · Answer

Thanks. BTW @Francesca_Marie, you got that yahoo.
I was just reading that....