Question

Verify that quadrilateral BCDE is a rhombus with vertices B(5, -1), C(-2, 0), D( -1, 7) and E(6, 6) by showing that all four sides are equal.

@Will.H

Answer 1

"by showing that all 4 sides are equal"
That means if all sides are equal then that shape would be a rhombus
we can calculate the lengths of the sides using the distence formula
\[\sqrt{(y2-y1)^2 + (x2-x1)^2}\]
Let's start with the points
B(5,-1) D(-1,7)
\[\sqrt{(7+1)^2 + (-1-5)^2}\] that would equal to? i don't have calculator lol
Do the same to the rest of the sides and see if they have the same length
\i'll brb

Answer 2

HINT:
rhombus has 4 sides...

Answer 3

normally, when you write BCDE, that is the order of the points
as you "go around the figure"
in other words, the four sides should be
BC
CD
DE
and EB

Answer 4

they want you to find the length of each side

Answer 5

right so mistakenly i calculated something else
So let's calculate BC shall we?
B(5,-1) C(-2,0)
\[\sqrt{((0 +1)^2 + (-2-5)^2}\]
which would equal to(using calculator) 50

Answer 6

Now as i said a rhombus has 4 sides in all options only C and D contain the 4 sides...

Answer 7

share your thoughts...

Answer 8

So anyway if you calculate the rest of the sides you will get them all equal to 50