help with factoring please
\[x ^{2} + 4x=0\]
To help, I will do the first step for you. \(\tt x^2 + 4x = 0 \color{red}{\rightarrow} x(x+4) = 0\) Do you know why I did that?
no that is what I am confused with
Change \(\tt x^2+4x\) to \(\tt x(x+4)\)
but how do I know to change it to that?
OK, let's look at the two terms \(\tt x^2\) and \(\tt4x\). Do you see a greatest common factor in the two terms?
I don't think
4?
Not quite. Do you know what a greatest common factor, or a factor, is?
yes, I just don't know how to find it in that one
Well, your common factor would be \(\tt x\), because x goes into \(\tt x^2\) and \(\tt 4x\). Think of \(\tt x^2\) as \(\tt x \times x\). Let's re-write our expression: \(\tt x \times x + 4x\). What is a common factor between each term? It's x
Ohh Okayy I see! Thank you so much!
Join our real-time social learning platform and learn together with your friends!