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OpenStudy (megan7):
\[x ^{2} + 4x=0\]
sammixboo (sammixboo):
To help, I will do the first step for you.
\(\tt x^2 + 4x = 0 \color{red}{\rightarrow} x(x+4) = 0\)
Do you know why I did that?
OpenStudy (megan7):
no that is what I am confused with
sammixboo (sammixboo):
Change \(\tt x^2+4x\) to \(\tt x(x+4)\)
OpenStudy (megan7):
but how do I know to change it to that?
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sammixboo (sammixboo):
OK, let's look at the two terms \(\tt x^2\) and \(\tt4x\). Do you see a greatest common factor in the two terms?
OpenStudy (megan7):
I don't think
OpenStudy (megan7):
4?
sammixboo (sammixboo):
Not quite. Do you know what a greatest common factor, or a factor, is?
OpenStudy (megan7):
yes, I just don't know how to find it in that one
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sammixboo (sammixboo):
Well, your common factor would be \(\tt x\), because x goes into \(\tt x^2\) and \(\tt 4x\).
Think of \(\tt x^2\) as \(\tt x \times x\). Let's re-write our expression: \(\tt x \times x + 4x\). What is a common factor between each term? It's x