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Algebra 20 Online
OpenStudy (megan7):

help with factoring please

OpenStudy (megan7):

\[x ^{2} + 4x=0\]

sammixboo (sammixboo):

To help, I will do the first step for you. \(\tt x^2 + 4x = 0 \color{red}{\rightarrow} x(x+4) = 0\) Do you know why I did that?

OpenStudy (megan7):

no that is what I am confused with

sammixboo (sammixboo):

Change \(\tt x^2+4x\) to \(\tt x(x+4)\)

OpenStudy (megan7):

but how do I know to change it to that?

sammixboo (sammixboo):

OK, let's look at the two terms \(\tt x^2\) and \(\tt4x\). Do you see a greatest common factor in the two terms?

OpenStudy (megan7):

I don't think

OpenStudy (megan7):

4?

sammixboo (sammixboo):

Not quite. Do you know what a greatest common factor, or a factor, is?

OpenStudy (megan7):

yes, I just don't know how to find it in that one

sammixboo (sammixboo):

Well, your common factor would be \(\tt x\), because x goes into \(\tt x^2\) and \(\tt 4x\). Think of \(\tt x^2\) as \(\tt x \times x\). Let's re-write our expression: \(\tt x \times x + 4x\). What is a common factor between each term? It's x

OpenStudy (megan7):

Ohh Okayy I see! Thank you so much!

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