The perimeter of an isosceles right triangle is 24 cm. How long are its sides?
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OpenStudy (calculusxy):
@jim_thompson5910
OpenStudy (calculusxy):
@Nnesha @skullpatrol @mathmale
OpenStudy (seratul):
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OpenStudy (calculusxy):
I thought of setting up an equation:
\(a + a + a\sqrt{2} = 24\)
OpenStudy (seratul):
What do you know about the hypotenuse?
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OpenStudy (calculusxy):
This would be a 45-45-90 triangle I suppose
OpenStudy (calculusxy):
The length would be \(a\sqrt{2}\)?
OpenStudy (seratul):
Simpler than that. Just in general, what do you know about it?
OpenStudy (calculusxy):
It's the longest side of the triangle
OpenStudy (seratul):
Correct. By the way, is this multiple choice? I am pretty sure there is more than one answer.
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OpenStudy (calculusxy):
Nope.
jimthompson5910 (jim_thompson5910):
OpenStudy (calculusxy):
@jim_thompson5910 That's where I am having the problem.
OpenStudy (seratul):
Welp, you got this jim :D
OpenStudy (calculusxy):
I only get up \(2a + a\sqrt{2} = 24\). I don't know whether I should factor it to \(a(2 + \sqrt{2}) = 24\) and if I do then how would I solve for \(a\)?
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jimthompson5910 (jim_thompson5910):
why not factor out the GCF 'a' to go from
\[\Large a+a+a\sqrt{2} = 24\]
to
\[\Large a(1+1+\sqrt{2}) = 24\]
jimthompson5910 (jim_thompson5910):
yes then you'd have
\[\Large a(2+\sqrt{2}) = 24\]
OpenStudy (calculusxy):
Would I divide both sides by \((2 + \sqrt{2})\)?
jimthompson5910 (jim_thompson5910):
essentially the left side is saying `some number 'a' times (2+sqrt(2))`
jimthompson5910 (jim_thompson5910):
yes you would divide both sides by (2+sqrt(2))
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OpenStudy (calculusxy):
So now I would have \(a = \frac{24}{(2 + \sqrt{2})}\)
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (calculusxy):
That's the complete answer? Like no more simplifying?
jimthompson5910 (jim_thompson5910):
you can rationalize the denominator if you want
jimthompson5910 (jim_thompson5910):
or convert to decimal form to get an approximate answer
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