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OpenStudy (calculusxy):
OpenStudy (calculusxy):
@jim_thompson5910
OpenStudy (calculusxy):
I mainly need help with the last question about how the slope of the line can be determined from its parametric equations
jimthompson5910 (jim_thompson5910):
when t = -1, what is the value of x?
OpenStudy (calculusxy):
Can you give me a moment please? I will be back in a couple of seconds
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jimthompson5910 (jim_thompson5910):
ok
OpenStudy (calculusxy):
I am back
jimthompson5910 (jim_thompson5910):
tell me what you get
OpenStudy (calculusxy):
x = -1
jimthompson5910 (jim_thompson5910):
incorrect
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OpenStudy (calculusxy):
I am sorry I did 1 instead of -1
jimthompson5910 (jim_thompson5910):
x = -4 + 3t
x = -4 + 3(-1)
x = -4 - 3
x = ????
OpenStudy (calculusxy):
But x = -7 ?
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
when t = -1, y = ????
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OpenStudy (calculusxy):
y = -1
jimthompson5910 (jim_thompson5910):
yes so we know that (-7, -1) is one point on this line
jimthompson5910 (jim_thompson5910):
when t = 0, what is the value of (x,y) ?
OpenStudy (calculusxy):
x = -4
y = 1
jimthompson5910 (jim_thompson5910):
so (-4,1) is another point on this line
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jimthompson5910 (jim_thompson5910):
when t = 2, what is the value of (x,y) ?
OpenStudy (calculusxy):
x = 2
jimthompson5910 (jim_thompson5910):
y = ??
OpenStudy (calculusxy):
y = 5
jimthompson5910 (jim_thompson5910):
yes
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jimthompson5910 (jim_thompson5910):
so (2,5) is that third point
jimthompson5910 (jim_thompson5910):
to prove it's collinear, you need to show that the slope is the same no matter which 2 points you pick
use the slope formula
\[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\]
OpenStudy (calculusxy):
Since the slope from one point to the other is the same from Point A to B and Point B to C, we can prove that it's collinear. Slope = 2/3
jimthompson5910 (jim_thompson5910):
ie, let
point A = (-7,-1)
point B = (-4,1)
point C = (2,5)
you need to show that
slope of line segment AB = slope of line segment BC = slope of line segment AC
OpenStudy (calculusxy):
Line segment AB = 2/3
Line segment BC = 4/6
Line segment AC = 6/9
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OpenStudy (calculusxy):
These are all of the slopes
jimthompson5910 (jim_thompson5910):
they all reduce to 2/3, so yes, the points are collinear
OpenStudy (calculusxy):
What about the question for how I should derive the slope from its parametric equations?
jimthompson5910 (jim_thompson5910):
You would just explain to the teacher that you found the points that correspond to the given t values. Then you use the slope formula
OpenStudy (calculusxy):
Oh okay! Thanks again :)
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jimthompson5910 (jim_thompson5910):
no problem
OpenStudy (calculusxy):
A couple more? Please
OpenStudy (calculusxy):
It's Exeter math and it's geometry on top of that :(
jimthompson5910 (jim_thompson5910):
ok go ahead
OpenStudy (calculusxy):
Thank you SSOOOOOO SOOOO much!
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