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Mathematics 12 Online
OpenStudy (calculusxy):

Math ...

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@jim_thompson5910

OpenStudy (calculusxy):

I mainly need help with the last question about how the slope of the line can be determined from its parametric equations

jimthompson5910 (jim_thompson5910):

when t = -1, what is the value of x?

OpenStudy (calculusxy):

Can you give me a moment please? I will be back in a couple of seconds

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (calculusxy):

I am back

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (calculusxy):

x = -1

jimthompson5910 (jim_thompson5910):

incorrect

OpenStudy (calculusxy):

I am sorry I did 1 instead of -1

jimthompson5910 (jim_thompson5910):

x = -4 + 3t x = -4 + 3(-1) x = -4 - 3 x = ????

OpenStudy (calculusxy):

But x = -7 ?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

when t = -1, y = ????

OpenStudy (calculusxy):

y = -1

jimthompson5910 (jim_thompson5910):

yes so we know that (-7, -1) is one point on this line

jimthompson5910 (jim_thompson5910):

when t = 0, what is the value of (x,y) ?

OpenStudy (calculusxy):

x = -4 y = 1

jimthompson5910 (jim_thompson5910):

so (-4,1) is another point on this line

jimthompson5910 (jim_thompson5910):

when t = 2, what is the value of (x,y) ?

OpenStudy (calculusxy):

x = 2

jimthompson5910 (jim_thompson5910):

y = ??

OpenStudy (calculusxy):

y = 5

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

so (2,5) is that third point

jimthompson5910 (jim_thompson5910):

to prove it's collinear, you need to show that the slope is the same no matter which 2 points you pick use the slope formula \[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\]

OpenStudy (calculusxy):

Since the slope from one point to the other is the same from Point A to B and Point B to C, we can prove that it's collinear. Slope = 2/3

jimthompson5910 (jim_thompson5910):

ie, let point A = (-7,-1) point B = (-4,1) point C = (2,5) you need to show that slope of line segment AB = slope of line segment BC = slope of line segment AC

OpenStudy (calculusxy):

Line segment AB = 2/3 Line segment BC = 4/6 Line segment AC = 6/9

OpenStudy (calculusxy):

These are all of the slopes

jimthompson5910 (jim_thompson5910):

they all reduce to 2/3, so yes, the points are collinear

OpenStudy (calculusxy):

What about the question for how I should derive the slope from its parametric equations?

jimthompson5910 (jim_thompson5910):

You would just explain to the teacher that you found the points that correspond to the given t values. Then you use the slope formula

OpenStudy (calculusxy):

Oh okay! Thanks again :)

jimthompson5910 (jim_thompson5910):

no problem

OpenStudy (calculusxy):

A couple more? Please

OpenStudy (calculusxy):

It's Exeter math and it's geometry on top of that :(

jimthompson5910 (jim_thompson5910):

ok go ahead

OpenStudy (calculusxy):

Thank you SSOOOOOO SOOOO much!

jimthompson5910 (jim_thompson5910):

sure thing

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