f(x) = 2x + 5, g(x) = X - 5 / 2 A. Graph the functions f(x) and g(x) on the same coordinate plane. You may use technology to create the graph of the functions or submit a handwritten graph. B. In two or more complete sentences, explain how to use the graphs of f(x) and g(x) to prove that the functions are inverses of each other. I don't understand what it is I have to do.
First you would plot these two functions....Were you able to do this?
f(x) is blue g(x) is orange.
Would they be inverses of each other because they end up going in opposite directions of the coordinate plane?
So so sorry Im trying to refresh on finding inverse....
It's okay.
You're helping me so there really is no need to apologize.
You would need to use... \(\huge{f(g(x))=g(f(x))=x}\) So we would substitute x for the opposite equation.... So lets do `f(x)` first... We have \(\huge{f(x)=2x+5}\) Now we substitute `g(X)` for x.... \(\huge{f(x)=2(x-\frac{5}{2})+5}\) Simplify...
\[2x - 2\frac{ 5 }{ 2 } (im assuming) + 5\]
*im assuming
I actually got \(\Large{f(x)=2x}\)
oh. How did you get that?
Wait is it \(\Large{g(x)=\frac{x-5}{2}}\) or is it the way I have been writing?
it's \[g(x) = \frac{ x - 5 }{ 2 }\]
OOOOOoooo well then I though it was the other way cause you didnt put parenthesis so I didnt know sorry
My fault, sorry.
So our equation is.... \(\huge{f(x)=2(\frac{x-5}{2})+5}\) So 2 multiplied by a fraction of 2 cancels out the two... and 5 (fractions) added by 5 cancels so.... \(\huge{f(x)=x}\)
I would be left with f(x) = \[\frac{ x }{ 2 }\] right?
Not quite. |dw:1474657990676:dw|
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