Question

∑(n^2)
from n= 0 to n =∞
how can i solve it and show that is equal to ∞

Answer 1

Let that helps you.

Answer 2

actually, i didn't understand

Answer 3

@3mar

Answer 4

@mathmale

Answer 5

\[\sum_{0}^{\infty}n^2=\frac{ n(n+1)(2n+1) }{ 6 }|0 \rightarrow \infty | \rightarrow \infty\]
or
\[\sum n^2=1^2+2^2+3^2+4^2+...... =1+4+9+16+....\rightarrow \infty~ as~ n \rightarrow \infty\]

Answer 6

it's very clear now, thanks a lot @3mar @sshayer

Answer 7

yw

Answer 8

I did not do anything, friend.
Thanks a lot.

Answer 9

and thanks for the medal!