Question

Simplify completely the quantity x squared plus x minus 12 over quantity x squared minus x minus 20 divided by the quantity 3 x squared minus 24 x plus 45 over quantity 12 x squared minus 48 x minus 60.

Answer 1

Is this what it looks like?
\[\large \frac{ \frac{ x^2+x-12 }{ x^2-x-20 } }{ \frac{ 3x^2-24x+45 }{ 12x^2-48x-60 }
}\]

Answer 2

Yes

Answer 3

first you can flip the bottom fraction over and multiply instead of divide..
\[\large \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } }=\frac{ a }{ b }*\frac{ d }{ c }\]

Answer 4

\[\large \frac{ x^2+x-12 }{ x^2-x-20 }*\frac{ 12x^2-48x-60 }{ 3x^2-24x+45 }\]

Answer 5

Ok I get it

Answer 6

Then you can pull a factor of 12 from one and a 3 from another...
\[\large \frac{ x^2+x-12 }{ x^2-x-20 }*\frac{ 12(x^2-4x-5) }{ 3(x^2-8x+15) }\]

Answer 7

And factor all four of those things..
\[\large \frac{ (x-3)(x+4) }{ (x-5)(x+4) }*\frac{ 12(x-5)(x+1) }{ 3(x-5)(x-3) }\]

Answer 8

the 12/3 reduces to 4/1
and a bunch of those quantities cancel from top and bottom
\[\frac{ 4(x+1) }{ x-5 }\]

Answer 9

Thats all you can do ..

Answer 10

Ahh ok. I kept on running into walls trying to solve. Thanks :)

Answer 11

welcome