Question

How did I do this wrong?

Answer 1

http://prntscr.com/cm1e8n

Answer 2

@LannyXX

Answer 3

3y^2 + 4y - 13 = y^2 - 2

Answer 4

Isn't it 3y^2+4y-13 + -y^2+2?

Answer 5

Well the basic rules are, y + y^2 = y + y^2 you cannot miss with that. if it helps, you can think of it like
3 APPLES + 4 ORANGES - 13 = ONE APPLE - 2,
can you tell me how many apples, oranges, and numbers were subtracted?

Answer 6

Your quantity was -13+2...? Did you make a typo?
\[\large 3y^2 +4y - 13-(\text{something}) = y^2 -2\]Solve for something.

Answer 7

why did you write -y^2 + 2 on the screenshot, when it's y^2 - 2?

Answer 8

i really am not sure lol. I was thought to switch the middle sign and switch the rest after.

Answer 9

So for example if I had (3y^2+4y-13) - (y^2-3)

becomes

3y^2+4y-13 + -y^2+3

Answer 10

the minus sign distributes over EVERYTHING inside the parenthesis :0

Answer 11

oh you did that, good :P i'm sleepy

Answer 12

But that isn't what you're given. It says she subtracted a quantity from 3y^2 + 4y - 13, NOT that she subtracted y^2 - 2 from it.

Answer 13

so its just y^2-2?

Answer 14

The first sentence of the question translates to \[\large 3y^2 +4y - 13-(\text{something}) = y^2 -2\]

Answer 15

"and produced" means "was equal to"

Answer 16

oh so P1 just means produce?

Answer 17

P1 is just a name they gave to "something".

Answer 18

ok and something is what I have to find

Answer 19

I don't understand how.

Answer 20

5 - X = 3
solve for X? it's pretty much the same procedure. just don't add y^2's with y's with no y's.

Answer 21

(3y^2+y^2) + 4y + ( -13-2)

Answer 22

like if you see y^2 + y - 4y^2 that equals -3y^2 + y.

Answer 23

yes like that!

Answer 24

are the addition signs correct?

Answer 25

solve for SOMETHING.
Weird polynomial - SOMETHING = some other weird polynomial

Answer 26

lol I only grouped the same exponents together. I have no clue what to do.

Answer 27

3y^2 + 4y - 13 - P = y^2 -2
solve for P. Why are you confused? this is like saying
P1 = 3y^2 + 4y - 13
P2 = y^2 - 2
P1 - P = P2. Solve for P.
Easy, P1 - P + P = P2 + P
P1 - P2 = P2 - P2 + P
P = P1 - P2, right?

Answer 28

\[\large 3y^2 +4y - 13-(\text{something}) = y^2 -2 \]First add something to both sides\[\large 3y^2 +4y - 13 = y^2 -2 +(\text{something})\]then subtract y^2 from both sides\[\large 3y^2 +4y - 13-y^2 = -2 +(\text{something})\]and add 2 to both sides\[\large 3y^2 +4y - 13-y^2+2 = (\text{something})\]and simplify by combining like terms

Answer 29

Well okay I found 2y^2+4y-11

Answer 30

I understand how to solve but I do not know what to put into the box.

Answer 31

you put SOMETHING; what needs to be subtracted.

Answer 32

I don't know lol

Answer 33

well it's the variable something! ahahah

Answer 34

Is it what I solved?

Answer 35

y^2

Answer 36

yes!
we said the polynomial - SOMETHING = otherPoly
you solved for SOMETHING! that's exactly what you subtracted!

Answer 37

wait so yes its y^2?

Answer 38

Na uh. It's the complete combining of this:
Something = 3y^2 + 4y - 13 - y^2 + 2

Answer 39

Because I subtracted 3y^2 with y^2

Answer 40

You only subtracted that? Why?

Answer 41

no I also did -13+2

Answer 42

And 4y didn't need to be subtracted

Answer 43

ok so what's the final solution?
something = ???

Answer 44

whatever that solution is, is what you put in the first box!

Answer 45

2y^2+4y-11 was my solution

Answer 46

thats what goes in box???

Answer 47

3y^2 +4y -13 - 2y^2 -4y + 11 = y^2 -2
WOO! look at that.

Answer 48

2y^2 +4y^ -11 does! why are you confused by what goes into the box?
it said subtract something from 3y^2 +4y -13, and you will get y^2 - 2.
we just figured what that very "something" is!

Answer 49

lol k it just doesn't make sense why wouldn't they just say whats the solution?

Answer 50

well, it's kinda like having
A - X = B
they know A, they know B.
They're asking you "what do I take from A to get B????" the solution to this QUESTION is X.
It's not the answer B. A solution is not what's alone in an equation. it's just the answer to a question or problem, sometimes they're the same sometimes not.

Answer 51

Aha I see now.

Answer 52

What goes in other two boxes?

Answer 53

I mean the main concept I understand. The only thing I don't understand is their vocabulary used.

Answer 54

Third box looks correct though right?

Answer 55

I am guessing P1 = the SOMETHING we calculated; what's in the first box.
So it says you subtracted from the first poly P1, to get... the second poly. You just copy that down.
How did you do it?? You choose something appropriate. Yeah it's weird, I guess it assesses your procedure ahahaha

Answer 56

so i'm saying the second box is the second poly: y^2 - 2, I dunno why you flipped signs.

Answer 57

Oh I see

Answer 58

Subtraction property of Equality ahahahaha that sounds so fancy.

Answer 59

Now this makes sense then! lol

Answer 60

Yea i know. Why does math have to be so fancy? :p

Answer 61

I don't know. It increases accuracy in speech I think. hehe

Answer 62

and explicitness too.

Answer 63

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Answer 64

Yea, probably lol

Answer 65

Got it correct now! :)

Answer 66

Thanks to you and agent very nice explaining! :)

Keep up the good work.

Answer 67

You gained y^2 - 2 exp, where y equals the number of cookies Ms.Mary has!

Answer 68

YES FINALLY! :D

Answer 69

hehe