Question

Please help. Passes through (-1,4) perpendicular to 3x+2y=9

Answer 1

Okay so you should start off by putting that equation into slope-intercept form. It will be easier to work with that way.

Answer 2

Question is incomplete

Answer 3

You can assume its asking for a line with those parameters

Answer 4

As @iTz_Sid said, we must put the equation into slope-intercept form.

\[3x+2y=9 \]

Subtract 3x from both sides

\[2y = -3x + 9\]

Divide the entire equation by 2

\[y = \frac{ -3}{ 2 }x + \frac{ 9 }{ 2 }\]

Answer 5

Oh! Let me do the problem really quick and see if we get the same answer

Answer 6

We need the slope perpendicular to -3/2x, so we take the opposite reciprocal.

Switch the numerator(-3) with the denominator(2). We get 2/-3. Then we change the negative sign to a positive sign.

The slope 2/3 is perpendicular to -3/2

Answer 7

Ok, I won't write any further steps :P

Answer 8

Okay so I got y= 2/3x+4/3

Answer 9

How did you get 4/3

Answer 10

Oh as your final answer?

Answer 11

Yes

Answer 12

If u have an equation of format ax+by+c=0. Then a line perpendicular to this line shall be ax-by+c' where c' is another constant

Answer 13

3x+2y-9=0

Perpendicular line is
3x-2y+c'=0
Replace x &y by -1 & 4 respectively to get c'

Answer 14

Thus form the final equation

Answer 15

So am I wrong with y=2/3x+4/3

Answer 16

Yes

Answer 17

Alright so I used y-4=2/3(x-4)

Answer 18

Why x-4

Answer 19

I used the y-y1=M(x-x1) formula

Answer 20

oh I see! I plugged in 4

Answer 21

yeah c;

Answer 22

So y=2/3x+21/12

Answer 23

woah

Answer 24

no

Answer 25

What did you start with?

Answer 26

Y-4= 2/3(x+1)

Answer 27

Then what did you do next

Answer 28

distribute 2/3

Y-4= 2/3x+ 2/3

Answer 29

Ok, then what next

Answer 30

ADD 4 to 2/3

Answer 31

oh! I found my mistake. So my answer was y= 2/3x+ 14/3

Answer 32

is that right

Answer 33

Yes, sorry ate dinner

Answer 34

No worries :) thank you so much