Question

Find the number of solutions of the equation 5t2 + 3t − 7 = 0 by using the discriminant.
one real solution
three real solutions
two real solutions
no real solutions

Answer 1

Discriminant=\(b^2-4ac\)
5t^2+3t-7=0
b=3
a=5
c=-7

Answer 2

Find discriminant if it comes less than 0 then the equation has no real solution.

Answer 3

If it comes equals to zero than both roots are equal

Answer 4

& real

Answer 5

But how does that tell me the number of solutions

Answer 6

Sorry, it didnt update!

Answer 7

If discriminant is greater than zero then it implies that equation has two unequal real roots

Answer 8

And moreover the highest degree determines how many roots will the equation possess

Answer 9

The highest degree here is 2 so number of roots are two

Answer 10

If it comes out real, then what does the two and three real solutions mean?

Answer 11

Discriminant tells u whether the roots r real or not

Answer 12

There cannot be 3 roots of an equation having highest degree as 2

Answer 13

In the options it has, one real solution, two real solutions nad three? Do I ignore the two and three options?

Answer 14

From highest degree u learnt that there will be 2 roots of the equation.

From discriminant determine whether the roots will be real or not

Answer 15

U may ignore 2nd option