What is the equation of the line that passes through the points (−2, 3) and (2, 7)?
may I help?
please
ok
This is the equation form of the line passes through two points: \[\frac{ y_2-y_2 }{ x_2-x_1 }=\frac{ y=y_1 }{ x-x_1 }\] All you need is to substitute with the two points in the equation
So I found the slope.. and it was 1 Do i need that to plug in?
yes the slope is 1 correct
im confused about how to use the formula you gave
one minute please
okay
yes i am here
I am sorry for late!
no problem
the left side is for slope the right side is to y and x
as the slope is 1, put it instead of the left side.
I wrote an equation that looked like this : Y-3=1(x-(-2)
Great! You did it. Some arrangement
but then I wound up getting y+1x-1
Y=1x-1 I mean
\[\frac{ y-3 }{ x-(-2) }=1\] \[y-3=x+2\] \[y=x+5\] and this this the graph of that line
The possible answers i was given were: x − y = −1 x − y = −2 x − y = − 5 x − y = − 6
got it? If you stuck to anything, tell me.
Out of these choices, is it the first one? x − y = −1 x − y = −2 x − y = − 5 x − y = − 6
Easy if we rearrange the last form, we get \[y=x+5\] \[y-y=x+5-y\] \[x-y-5=0\] \[x-y-5+5=0+5\] \[x-y=-5\] Hope that helps
Ohh I see, Thank you!
Thank you for learning!!
and Thank you for the medal!
y-y1=m(x-x1) \[m=\frac{ y2-y1 }{ x2-x1 }\]
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